The kinetic energy K (in joules) of a falling apple is represented by K=v squared divided by 2 where v is the speed of the apple (in meters per second). How fast is the apple traveling when the kinetic energy is 32 joules?
Accepted Solution
A:
do subsitution
energy (k)=32
so 32=(1/2)v^2 (I'm pretty sure it is K=(1/2)mv^2, but ok) times 2 both sides 64=v^2 sqrt both sides 8=v